Motion In Straight Line
Motion is the change of position of an object from one place to another. There are two types of motions; i.Circular motion-Is the motion of an object in a circle. Examples; a/. motion of the electron around the nucleus of an atom b/.revolutionary movement of the earth around the sun. ii.Linear motion-Is the motion of an object in a straight line.
Acceleration
Acceleration
is the rate of change of velocity or is the change in velocity per unit
time Mathematically. Acceleration, a = (final velocity, v – initial
velocity, u)/time, t
is the rate of change of velocity or is the change in velocity per unit
time Mathematically. Acceleration, a = (final velocity, v – initial
velocity, u)/time, t
Velocity Time-graph
Interpret velocity time-graph
This
is velocity against time graph. Consider a body accelerating uniformly
from rest to a certain velocity v within time t. This can be represented
graphically as shown below;
is velocity against time graph. Consider a body accelerating uniformly
from rest to a certain velocity v within time t. This can be represented
graphically as shown below;
Distance
- The distance x moved by the body is given by the area under the curve.
- In this case is the area of triangle OBC.
Acceleration.
- The acceleration is given by the slope of the triangle OBC.
The Acceleration of a Body
Determine the acceleration of a body
Example 1
A
car starts from rest and accelerates to a velocity of 120m/s in one
minute. It then moves with this speed for 40seconds finally decelerates
to rest after another 2 minutes. Calculate;
car starts from rest and accelerates to a velocity of 120m/s in one
minute. It then moves with this speed for 40seconds finally decelerates
to rest after another 2 minutes. Calculate;
- the distance travelled
- the total time taken for the whole motion
- the deceleration
- the average velocity
Soln
1st stage; acceleration u =0, v = 120m/s,t1 =1min=60s
2nd stage; uniform vel u=v=120m/s,t2=40s
3rd stage; Deceleration u=120m/s,v=0,t3=2min=120s
- 1st stage; s =average vel x time = ( (120+0)/2)60 = 3600m
- 2nd stage; s = vt = 120 x 40 = 4800m
- 3rd stage; s = average vel x time = ((v=u)/2)t = ((120+0)/2)120 = 7200m
Total distance, s T =3600+4800+7200 =15600m
Total time taken = 60 + 40 + 120 = 220s
from v = u + at
120 = 0 + 60a
60a = 120
a = 2m/s.
Average velocity = total distance/time
va = 15600/220
va = 71m/s
The Concept of Retardation
Explain the concept of retardation
Deceleration
(retardation) is the rate of decrease of velocity or is the decrease in
velocity per unit time. Uniform acceleration or retardation Is the one
whereby the rate of increase or decrease of velocity is constant or it
doesn’t change.
(retardation) is the rate of decrease of velocity or is the decrease in
velocity per unit time. Uniform acceleration or retardation Is the one
whereby the rate of increase or decrease of velocity is constant or it
doesn’t change.
Note;
- when a body starts from rest or is brought to rest, its velocity is zero
- when the velocity of a body is constant or uniform, its acceleration is zero
- when the velocity of a moving object increases, its acceleration becomes positive
- when the velocity of a moving object decreases, its acceleration becomes negative called retardation.
Equations of Uniformly Accelerated Motion
Equation of Uniformly Accelerated Motion
Derive equation of uniformly accelerated motion
There are three equations of motion;
Newton’s first equation of motion
It is given by; v = u + at
whereby;
- u = initial velocity
- v = final velocity
- a = acceleration
- t = time taken
PROOF;
From the formula of acceleration; a = (v-u)/t
- at = v – u at + u = v
- v = u + at proved!
Newton’s second equation of motion
It is given by
whereas;
- s=distance travelled
- u=initial velocity
- t=time taken
- a=acceleration
PROOF;
Suppose
an object starts from rest with intial vel,u to final vel,v after time t
The distance ,S moved is given by S = Average vel x time S =( (u+v)/2)t
an object starts from rest with intial vel,u to final vel,v after time t
The distance ,S moved is given by S = Average vel x time S =( (u+v)/2)t
Substitute Newtons first eqn,gives; S = ((u+u+at)/2)t
S = ((2u+at)/2)t
S = ut + 1/2at. proved!
Newtons third equation of motion
It is given by V2 = U2+ 2as
where v=final velocity; u =initial velocity; a = acceleration; s = distance covered.
PROOF
From Newton’s first eqn; v = u + at
Equations of Accelerated Motion in Daily Life
Apply equations of accelerated motion in daily life
Activity 1
Apply equations of accelerated motion in daily life
The Concept of Gravitational Force
Explain the concept of gravitational force
The
acceleration of a free falling body is known as the acceleration due to
gravity denoted by g and controlled gy gravitational force of the
earth.
acceleration of a free falling body is known as the acceleration due to
gravity denoted by g and controlled gy gravitational force of the
earth.
When
two bodies of different masses are released from a certain height h
above the ground, they will reach the ground at different times with the
heavier one reaching earlier before the lighter one.
two bodies of different masses are released from a certain height h
above the ground, they will reach the ground at different times with the
heavier one reaching earlier before the lighter one.
The
reason is that the air resistance is more effective on lighter bodies
than in heavier bodies, consequently this affect acceleration due to
gravity in a reverse manner.
reason is that the air resistance is more effective on lighter bodies
than in heavier bodies, consequently this affect acceleration due to
gravity in a reverse manner.
But
dropping a light object and a heavy object in a vacuum they will reach
the ground at the same time due to the absence of air resistance effect.
dropping a light object and a heavy object in a vacuum they will reach
the ground at the same time due to the absence of air resistance effect.
Consider the following two cases;
Case I
Consider a body falling freely from a certain height h and uses time t to reach the ground.
In this case: acceleration, a = acceleration due to gravity g
Initial velocity, u = 0
Final velocity, v.
Case II
Consider
a body thrown vertically upwards from the ground with an initial
velocity u to a certain height h and then comes back to the ground after
time t.
a body thrown vertically upwards from the ground with an initial
velocity u to a certain height h and then comes back to the ground after
time t.
In this case;
- Acceleration, a = -g
- Initial velocity = u
- Velocity at h = 0
- Final velocity at the ground = v
Acceleration due to Gravity
Determine acceleration due to gravity
A
simple pendulum is a small heavy body suspended by a light inextensible
string from a fixed support and it is normally used to determine
acceleration due to gravity.
simple pendulum is a small heavy body suspended by a light inextensible
string from a fixed support and it is normally used to determine
acceleration due to gravity.
It
is made by attaching a a long thread to a spherical ball called a
pendulum bob. The string is held at a fixed at a fixed support like two
pieces of wood held by a clamp and stand.
is made by attaching a a long thread to a spherical ball called a
pendulum bob. The string is held at a fixed at a fixed support like two
pieces of wood held by a clamp and stand.
If
the bob is slightly displaced to position B,it swings to and from going
to C through O and back to B through O. When the pendulum complete one
cycle/revolution the time taken is called the period of oscillation, T.
the bob is slightly displaced to position B,it swings to and from going
to C through O and back to B through O. When the pendulum complete one
cycle/revolution the time taken is called the period of oscillation, T.
Definitions
- Period ,T is the time taken by the pendulum bob to complete one complete cycle.
- Angular displacement is the angle made between the string and the vertical axis when the bob is displaced to a maximum displacement.
- Amplitude is the maximum displacement by which the pendulum has been displaced.
- Length of pendulum is the length of the string from the point of attachment on the wooden pieces to the canterof gravity of the bob.
From
the experiments, it has been observed that, changing the weight of the
bob and keeping the same length of pendulum, the period is always
constant provided that all swings are small though they may be different
in size.
the experiments, it has been observed that, changing the weight of the
bob and keeping the same length of pendulum, the period is always
constant provided that all swings are small though they may be different
in size.
The period T of the pendulum is given by;
Where; l = length of pendulum; g = acceleration due to gravity
Also
It follows that if we plot a graph of l against T. it is going to be a straight line with a slope g/4Π2and y –intercept equal to 0.
When
the bob is raised to point B it will gain potential energy and the bob
will swing due to the conservation of energy from potential to kinetic
energy.
the bob is raised to point B it will gain potential energy and the bob
will swing due to the conservation of energy from potential to kinetic
energy.
- At B and C all energy is P.E.
- At O all energy is K.E.
- P.E at B = K.E at O.
If
the pendulum swung in vacuum the oscillations would have been
continuous. But practically, air friction causes losses of energy of the
pendulum bob. That is why after a certain time the oscillations cease.
the pendulum swung in vacuum the oscillations would have been
continuous. But practically, air friction causes losses of energy of the
pendulum bob. That is why after a certain time the oscillations cease.
The Application of Gravitational Force
Explain the application of gravitational force
Activity 2
Experiment
Aim: Determination of acceleration due to gravity by using the simple pendulum.
Materials and apparatus: A simple pendulum, stand, clamps and stop watch.
Procedures
- Tie a piece of thread to a brass bob(about 100g)
- Suspend a bob with a thread between wooden pieces by clamping them on to a stand.
- Pull the bob slightly to one side and release the bob. Make sure the bob swings 50 complete oscillations.
- To be more accurate, perform three measurements for each length l of the pendulum.
- Repeat the procedures with l = 60cm and 50cm.
- Record the results as in the table below. -Plot the graph of l against T2
Results
| Length, l (cm) | Time for 50 oscillations. | T (s) | T² (s²) | |||
| t₁ (s) | t₂ (s) | t₃ (s) | Average(s) | |||
Observation
The graph obtained will be a straight line through the origin.
The slope of the graph is given by;
