TOPIC 5: APPROXIMATIONS
Measurements can be rounded to a certain number of significant figures.
Approximation– is a process of rounding numbers to a certain degree of accuracy.
A number can be rounded to a certain required place value such as to the nearest ten, hundred, and thousand
Rounding Off Numbers
Rounding off Whole Numbers to Given Place Values
Round off whole numbers to given place values
STEPS
When rounding a number, stand at the digit of the required place value, then look at the next digit to the right; if it is or more, round up (i.e, increase the digit of the required place value by 1) and if it is or less, do not change the digit of the required place value
Replace all the remaining digits to the right of the required place value with the zeros
Example 1
The population of Tanzania in a census of 2002 was 42,850,671. Round this to the nearest
million
ten million
Solution
The million digit is 2, since the next digit to the right is greater than 5, then we can increase 2 by 1 and put the remaining digits to the right of 2 zeros. There fore;42,850,671 ≈ 43,000,000
The ten million digit is 4, since the next digit to the right is less than 5, then we do not change 4 but we put the remaining digits to the right of 4 zeros. There fore;42,850,671 ≈ 40,000,000
Decimals to a Given Number of Decimal Place
Round off decimals to a given number of decimal place
STEPS
When rounding a decimal, stand at the digit of the required decimal place, then look at the next digit to the right; if it is or more, round up (i.e increase the digit of the required decimal by 1) and if it is or less, do not change the digit of the required decimal place
Replace all the remaining digits to the right of the required decimal place with the zeros
NOTE
The first digit after the decimal point is the first decimal place, the second digit after the decimal point is the second decimal place e.t.c
Example 0.568 is the first decimal place and is the second decimal place
Example 2
Round 0.24736 to the nearest
1 decimal place
2 decimal places
3 decimal places
Solution
0.24736≈ 0.02 (1 d.p)
0.24736≈ 0.025 (2 d.p)
0.24736≈ 0.0247 (1 d.p)
Significant Figures
Significant figures of a number – are the significant digits, counted from left of the number.The first significant figure must be non-zero; following significant figures may take any value.
A Number to a Given Number of Significant Figures
Write a number to a given number of significant figures
Is the number of significant digits including 0 if it is between the first and the last
Examples
13 – has two significant figures
709.43 – has five significant figures
0.0004001 – has four significant figures
STEPS
When rounding a number to a certain significant figure, stand at the digit of the required significant figure, then look at the next digit to the right; if it is or more, round up (i.e increase the digit of the required significant figure by 1) and if it is or less, do not change the digit of the required significant figure
Replace all the remaining digits to the right of the required significant figure with the zeros
Example 3
Given the number 45.274 round to
1 first significant figure
2 significant figure
significant figure
Solution
50
45
45.3
Example 4
Round 146 400 to
2 first significant figure
4 significant figure
3 significant figure
Solution
150 000
146 400
146 000
Approximations in Calculations
The Knowledge of Rounding Off of Numbers in Computations Involving Large Numbers and Small Numbers
Use the knowledge of rounding off of numbers in computations involving large numbers and small numbers
Approximation can be used in operation to check whether a calculation is correct or not, i.e in addition, subtraction, multiplication and divisione.g 446 x 45 = 20 070
The above calculation can be checked quickly whether it is correct or not by rounding each number to 1 significant figure and then multiply i.e 400 x 50 = 20 000
Therefore, the approximation of 20 000 is close to 20 0070 is correct.Before carrying an operation, each number in a calculation is rounded to 1 significant figure
Example 5
Find the approximate value of
Example 6
A school trip of 32 people went to a tour, which costs a transport fee of 580/- each people. What was the approximate total transport cost?
Solution
32 × 580 ≈30×600 = 18 000
The approximate transport cost was 18 000/-
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